Question

Could someone help me in 15 (a)

Answer 1

<RQP=<RQD+<DQP

So <DQP=180°-60°(Linear Angles)

=120°

So..

➡️<RQP=25°+120°=145°

<QRS=<QRA+<ARS

So <QRA=<RQD(Alternate interior Angles are same)

So <QRA=25°

Also given RS||PQ

So <QPE=<ARS(since RS||PQ)

So<QPE=180°- <CQP(Sum of Angles on same side is 180°)

Hence <QPE=180°-60°=120°

So <ARS=120°(since RS||PQ)

Hence

<QRS=25°+120°=145°

Hope it helped u ☺️

Answer 2

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