Question

could someone please solve the above question​

Answer 1

Answer:

Here is your answer...

Answer 2

Answer:

Let

2x+3y=0........ (1)

3x+5y=0........ (2)

By elimination method,

Multiplying equation (1) and (2) with 3 and 2 respectively, we get

3(2x+3y=0)

=. 6x+9y=0.......(3)

2(3y+5y=0)

=. 6x+10y=0.......(4)

Subtracting equation........(3) from equation....(4), we get,

6x+10y-(6x+9y)=0

6x+10y-6x-9y=0

10y-9y=0

y=0

Now putting the value of y in equation......(1),. we get

2x+3(0)=0

x=0

Therefore

x=0

y=0