Math, asked by lemon112007, 4 months ago

Could someone please solve this?

Attachments:

Answers

Answered by XxxxsingalshotXxxx
4

Answer:

(1+x)

dx

dy

−xy=1−x

dx

dy

+(

1+x

−x

)y=

1+x

1−x

∫pdx=∫

1+x

−x

=−∫

1+x

1+x−1

dx

=−∫1−

1+x

1

dx

=−x+log∣1+x∣dx

I.Fe

∫pdx

=e

log(1+x)−x

=

e

x

1+x

4.5y.

e

x

1+x

=∫

e

x

1−x

y

e

x

(1+x)

=∫e

−x

(1−x)

y(1+x)=e

x

c

−x

(+x)

y(1+x)=x

Answered by chowdarypravallika81
2

Answer:

Here is your answer please mark as me brain list dear it's important to me hope it's helps you

Attachments:
Similar questions