could u please help me? Find the three consecutive terms in an A.P whose sum is 18 and the sum of their squares is 140
ashishksharma:
answers are 5,6,7 and sum is 110 not 140
answersfor the question are 5,6,7 and sum is 110 not 140
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let the three terms be (a-1),a,(a+1)
sum =18
(a-1)+a+(a+1)=18
a-1+a+a+1=18
3a=18
a=6
(a-1)=5
(a+1)=7
sum =18
(a-1)+a+(a+1)=18
a-1+a+a+1=18
3a=18
a=6
(a-1)=5
(a+1)=7
the terms are 2,6,10
maybe
a=6 but d for question is 4
well i m sorry
Sorry for this comment but i think something went wrong with your answer
yup i got my mistake
i m sorry
Its ok bro.
please Edit your answer
Beacause you are marked as brainlist in this answer so your answer should be correct
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