Question

could you help me in doing this question by step by step

Answer 1

Answer:

Q1)) I) in ∆ABC the sum of all angles is 180°

and also angle ACB = X

65 + 55 + x = 180 ,, x = 180 - 120 ,, x = 60°

II) in ∆ECD same 60(x) + y + /DEC = 180°

now here /DEC = 55 ( linear pair with 125°)

60 + 55 + y = 180 ,, y = 180 - 115 ,, y = 65°

Q2) in ∆ABC the sum of all angles = 180°

80 + 60(30+30) + 2x = 180

2x = 180 - 140 ,, 2x = 40 ,, x = 20°

in ∆ADC ,

30 + y + 20(x) = 180 ,, y = 180 - 50 ,, y = 130°

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