Question

could you help me with this

Answer 1

1,2,3, ... 100

Here the terms in A.P. where a = 1, d = 1 and n = 100

As we know that from the formula of Sum :

$S_{n} = \frac{n}{2} [2a + (n - 1)d] \\ \\ = > S_{n} = \frac{100}{2} [2 \times 1 + (100 - 1)1] \\ \\ = > S_{n} = 50(2 + 99) \\ \\ = > S_{n} = 50 \times 101 = 5,050$

So, the sum of numbers 1 to 100 will be 5,050 ✔✔

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Hope it helps ☺

Fóllòw Më ❤

Answer 2

Answer:

no haha

Step-by-step explanation: