Question

Could you please answer the question? ​

Answer 1

Step-by-step explanation:

Given Equation of the plane is x + 2y - 3z - 6 = 0.    ------ (i)

Dividing (i) by √1² + 2² + (-3)² or, by √14

We get,

⇒ x/√14 + 2y/√14 - 3z/√14 - 6/√14 = 0

⇒ x/√14 + 2y/√14 - 3z/√14 = 6/√14

Which is the equation of the plane in the normal form.

∴ Length of the perpendicular is 6/√14.

Hope it helps!