Question

Could you please help me with this question?
Find the domain and range of the function f(x) = 4/sqrt(8-x).​

Answer 1

Step-by-step explanation:

Denominater shouldn't be zero, otherwise the function wont exist.

This gives us (8-x) should be greater than or equal to 0.

Implies x should be lesser than or equal to 8 is the domain.

Range is set of all real numbers.

Answer 2

Answer:

( -∞ , 8] & R

Step-by-step explanation:

f(x) = 4 /√ (8-x)

clearly...

x < 8 f(x) € R

and for x > 8 ; f (x) not defined

therefore. .

Domain of f(x) = ( -∞ , 8]

Range of f(x) €R