could you please solve q 15
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to find the solubility of a substance at a given temperature just subtract the separated amount of solute from the original solubility at 50
so the solubility at 40 degree = 28.6 -2.4
= 26.2
so the solubility at 40 degree = 28.6 -2.4
= 26.2
itsuj2:
ans is d
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