Math, asked by AaravGupta1234, 9 months ago

could you please solve the question-
tan 1° tan 2° tan 3° ... tan 89°
I will mark best answer as brainliest.

Answers

Answered by ravinder268

1

tan1°tan2°tan3°.........tan89°

=tan1°.[cot1°]tan2°[cot2°]........tan45°

we know that tanθcotθ=1

so,

1×1×1×1×1×·············will be equal to 1

and the value of tan45°=1

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