Question

Coulomb's force between alpha particle at a distance of 2r

Answer 1

$\large\underline{\bigstar \: \: {\sf Given-}}$

• Alpha particles of charges ${\sf Q_1 \: and \: Q_2 = 2\times 1.6 \times 10^{-19}C}$
• Distance between two particles (r) = 2r

$\large\underline{\bigstar \: \: {\sf To \:. Find -}}$

• Coulomb's force between alpha particles.

$\large\underline{\bigstar \: \: {\sf Formula \: Used -}}$

$\implies\underline{\boxed{\sf F = 9 \times 10^9 \dfrac{Q_1\times Q_2}{r^2}}}$

$\large\underline{\bigstar \: \: {\sf Solution-}}$

$\implies{\sf 9 \times 10^9 \dfrac{2\times 1.6 \times 10^{-19}\times 2 \times 1.6 \times 10^{-19}}{(2r)^2} }$

$\implies{\sf \dfrac{ 92.16\times 10^{-29}}{4r^2}}$

$\implies{\sf \dfrac{23.04 \times 10^{-29}}{4r^2} }$

$\large\underline{\bigstar \: \: {\sf Answer-}}$

Coulomb's force between particles is ${\bf \dfrac{23.04 \times 10^{-29}}{r^2} \: N}$