Question

count the number of electrons of Zn which are present in orbitals having only one nodal plane

Answer 1

Answer:

we know that Angular nodes(NODAL PLANE) of p subshell is 1

Electronic configuration of Zn :

$1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{10}$

orbitals $2p^{6}$ and $3p^{6}$  have 1 Nodal plane

The number of electrons of Zn present in orbitals having only one nodal plane are 12 electrons

Hope this is helpful

Answer 2

The Nodal plane is the plane in which the probability of finding electron is negligible.

Explanation:

Atomic number of Zinc is 30

Electronic configuration of Zinc=1s²,2s²,2p⁶,3s²,3p⁶,3d¹⁰,4s²

The total number of nodes=n-1

where n is the principal quantum number

in the electronic configuration of Zinc  1s²,2s²,2p⁶,3s²,3p⁶,3d¹⁰,4s²            The number of node is = (1-1)+(2-1+(2-1)+(3-1)+(3-1)+(3-1)+(4-1)

=1+1+1+2+2+2+3

= 12

The number of electrons of Zn which are present in orbitals having only one nodal plane is 12