Courtyard of 22 M long and 14m broad is to be made with bricks of length 25 cm and breadth is 60 cm find the number of bits required
Answers
Answered by
84
length of courtyard = 22m = 2200cm
breadth of courtyard= 14m = 1400cm
area of courtyard= 2200 × 1400
= 3080000cm^2
length of brick = 25cm
breadth = 60cm
ara = 25 × 60 = 1500cm^2
number of bricks required
= area of courtyard/ area of brick
= 308000 / 1500
= 2053 1/3 bricks
Answer:
--------------
required bricks =2053 1/3 bricks
breadth of courtyard= 14m = 1400cm
area of courtyard= 2200 × 1400
= 3080000cm^2
length of brick = 25cm
breadth = 60cm
ara = 25 × 60 = 1500cm^2
number of bricks required
= area of courtyard/ area of brick
= 308000 / 1500
= 2053 1/3 bricks
Answer:
--------------
required bricks =2053 1/3 bricks
Anonymous:
nice answer :)
Answered by
26
hey
_______
area of courtyard = 22*14m=308m^2 = 308*100*100 cm ^2 = 3080000cm^2
area of brick = 25*60cm^2=1500cm^2
req no bits = area of courtyard/area of brick
= 3080000/1500=2053
-(the real ans is 2053.33333.....) we cant write req no of bits in decimal so the ans is 2053
hope helped
____________
_______
area of courtyard = 22*14m=308m^2 = 308*100*100 cm ^2 = 3080000cm^2
area of brick = 25*60cm^2=1500cm^2
req no bits = area of courtyard/area of brick
= 3080000/1500=2053
-(the real ans is 2053.33333.....) we cant write req no of bits in decimal so the ans is 2053
hope helped
____________
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