Question

Cov
10
const uit
SO = 50m
a quador laleal PORS, Pozama
Sp=24cm SR=8cm and Ro=7cm​

Answer 1

In ||gm ABCD,

∠A + ∠B = 180°

(Sum of consecutive angles) But, ∠A = 75°

∴ ∠B = 180° – ∠A = 180° – 75° = 105°

∴ DBA = 105° -60° = 45°

But ∠CDB = ∠DBA (alternate angles)

= 45°

and ∠ADB = ∠DBC = 60°