Math, asked by seemasheikh1998, 6 months ago

.
cover
The distance between two railway у
stations is 1776 Em
TO
this distance an express trains
takes
5 irs
less than
train while
average speed
of
the
passenger
train
in
70 km h less
than that of
train
express
The time taken by
trave
passenger
the
passenger train to comptete
the​

Answers

Answered by mohantypreet2
0

Step-by-step explanation:

Let the speed of express train be x km/h

Let the speed of passenger train be y km/h

x=y+10..........(i)

Time is defined as the ratio of distance to speed.

Time of express train is less than passenger train by 2 h

x

400

+2=

y

400

...........(ii)

Substituting value of x from (i) in (ii), we get:

y+10

400

+2=

y

400

Rearranging terms, we get:

y

2

+10y−2000=0

y

2

+50y−40y−2000=0

(y+50)(y−40)=0

y=−50,40

Speed cannot be negative.

y=40

From equation (i), x=y+10=50

Hence,

average speed of express train is 50 km/h

average speed of passenger train is 40 km/h

Answered by arnab7184
0

Answer:

Let the speed of express train be x km/h

Let the speed of passenger train be y km/h

x=y+10..........(i)

Time is defined as the ratio of distance to speed.

Time of express train is less than passenger train by 2 h

x

400

+2=

y

400

...........(ii)

Substituting value of x from (i) in (ii), we get:

y+10

400

+2=

y

400

Rearranging terms, we get:

y

2

+10y−2000=0

y

2

+50y−40y−2000=0

(y+50)(y−40)=0

y=−50,40

Speed cannot be negative.

y=40

From equation (i), x=y+10=50

Hence,

average speed of express train is 50 km/h

average speed of passenger train is 40 km/h

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