Question

covert 29 base 10 and 11 base 10 into equivalent binary values ???​

Answer 1

$\textsf{\large{\underline{Answers}:}}$

• (29)₁₀ = (1110 1)₂
• (11)₁₀ = (1011)₂

$\textsf{\large{\underline{Solutions}:}}$

#1

Conversion is given as follows:

$\boxed{\begin{array}{c|c|c}\tt2&\tt29&\\ \tt2&\tt14&\tt1\\ \tt2&\tt7&\tt0\\ \tt2&\tt3&\tt1\\ \tt2&\tt1&\tt1\\ &\tt0&\tt1\end{array}}$

Now arrange the remainders obtained from bottom to top:

> (29)₁₀ = (1110 1)₂ (Answer)

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#2

Conversion is given as follows:

$\boxed{\begin{array}{c|c|c}\tt2&\tt11&\\ \tt2&\tt5&\tt1\\ \tt2&\tt2&\tt1\\ \tt2&\tt1&\tt0\\ &\tt0&\tt1\end{array}}$

Now arrange the remainders obtained from bottom to top:

> (11)₁₀ = (1011)₂ (Answer)

$\textsf{\large{\underline{Steps To Solve}:}}$

• Divide the number by 2.
• Write the quotient on the left and remainders obtained on the right.
• Repeat the above two processes until the quotient becomes 0.
• Now arrange the remainders obtained from bottom to top.
• Result obtained will be the binary equivalent of the given decimal number.