Question

covert A.B + B.C' into it's canonical SOP form​

Answer 1

Answer:

AB + BC + CA = AB

Explanation:

Y (A, B, C) = AB + BC + CA, this expression is a SOP expression, since we notice the Boolean function has three literals A, B and C, so each term of the Boolean expression must contain all the three literals to convert it into canonical SOP form. Therefore, = Y (A, B, C) = AB + BC + CA = AB