Cox 4x = Cox 2x, find the value of X
please help me out with it please
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Solution:-
Cos4x = Cos2x
Cos∅ = CosA
∅ = 2nπ ± A
4x = 2nπ ± 2x
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On taking +ve sign
4x = 2nπ + 2x
2x = 2nπ
x = nπ
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On taking -ve sign
4x = 2nπ - 2x
6x = 2nπ
x = 2nπ/6
x = nπ/3
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