Question

Cp is 20 for 64g oxygen cv is??

Answer 1

Answer:

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Explanation:

128 g of oxygen (molecular weight = 32) corresponds to 4 moles.

The enthalpy change is ΔH=nC

P

ΔT=4×7×100=2800 cal.

The change in internal energy is ΔU=nC

V

ΔT=4×5×100=2000 cal.

Answer 2

Answer:

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3.4J/K mol is the answer.

Explanation:

64g of oxygen corresponds to 2 moles now using formula

$cp - cv = nr$

n is number of moles and r is the universal gas constant.

Cv = 20 - 2(8.314)

Cv = 3.37J/Kmol.