Question

· CP is bisector of angle C of A ABC.
2. Given : CP is biser
A-
Prove : P is equidistant from AC and BC.​

Answer 1

Answer:

Angle ACP is congruent to PCB.........(Vertically opposite angles).

Angle ACB is congruent to PCB.........(Point C is common point).

Therefore C is the bisector...................(By A-A test).