Cp of the solid in the temperature renge 0‐15k can be calculated by
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0
Answer:
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Explanation:
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Answered by
0
Answer:
Amount of heat required, Q=∫dQ
=∫
T
1
=20
T
2
=30
mcdT
given C=DT
3
∴Q=∫
20
30
mDT
3
dT=mD∫
20
30
T
3
dT
=mD
4
1
[(30)
4
−(20)
4
]=
4
65
×10
4
mD
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