Question

cqn any ony solve this by elimination mathod 3a+2b=12 2a+3b=13. i can't solve it by elimination method but i solved it by substituting method can any one solve it

Answer 1

Answer:

2,3

Step-by-step explanation:

We have,

3a + 2b = 12    ----- (i)

2a + 3b = 13    ------- (ii)

Now,

On solving (i) * 2 & (ii) * 3, we get

6a + 4b = 24

6a + 9b = 39

---------------------

         5b = 15

           b = 3.

Substitute b = 3 in (i), we get

⇒ 3a + 2b = 12

⇒ 3a + 6 = 12

⇒ 3a = 6

⇒ a = 2

Therefore, the values of a and b = 2 and 3.

Hope it helps!

Answer 2

Answer:

Step-by-step explanation:

3a+2b=12 ....×2

2a+3b=13 .....×3

6a+4b = 24

6a+9b = 39

On changing signs

-5b=-15

5b=15

B=3

Putting value of b

3a+2b=12

3a+2(3)=12

3a+6=12

3a=12-6

3a=6

A=2

Hope it works

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