Question

[Cr(H2O)4Cl2]NO3 Calculate oxidation number of Cr

Answer 1

[Cr(H2O)4Cl2]NO3

NO3 has -1 charge.

So [Cr(H2O)4Cl2] will have +1 net charge.

H2O is neutral.
Cl has -1 charge
let Cr has charge x.

x + 4×0 + 2×(-1) = +1

=> x - 2 = 1

=> x = +3

So oxidation number of Cr is +3

Answer 2

Answer:

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