Question

(cr (h2o)5cl)+2 oxidation number of metal​

Answer 1

Oxidation number of metal in complex [Cr(H₂O)₅Cl]⁺²

Explanation:

• The given compound is a complex compound which contain chromium as central metal with H₂O molecule and Chloride group as chelating agent.
• Oxidation state of metal in a complex compounds can be determine by charge contribution by chelating groups. Chelating group can be anionic, cationic as well as neutral species.
• In the given complex, molecule H₂O is a neutral group thus it contribute zero charge whereas chloride group is an anionic species which contribute -1 charge.
• To calculate oxidation number of metal, lets assume oxidation number on metal Cr is x.
• So, oxidation number of metal in complex [Cr(H₂O)₅Cl]⁺² is-

                   x + 5(0) + (-1) = (+2)

                    x + 0 - 1  = +2

                    x - 1 = +2

                    x = 2+1

                   x = +3

Therefore, oxidation number of metal Cr in complex [Cr(H₂O)₅Cl]⁺² is +3.