Question

Cr(OH) + IO3- = Cr3+ + I-
Balance

Answer 1

Answer:

IO3 - + 3H2O+2Cr(OH)3 ---------> 2CrO4 2- 8 H2O +I- 6OH-

Explanation:

We will balance Cr(OH) WITH Cro4 2- and IO3 - with I-

Cr(OH)3 gives Cr+3 + 3OH-

Here, OH shows that the equation should be balanced in basic medium

Cr+3--------->(CrO4)2-

Cr+3--------->(CrO4)2- +4H2O

8OH- + Cr+3--------->(CrO4)2- + 4H2O

8OH- + cr+3---------->4H2O+(CrO4)2-+ 3e- ----------(1)

Now,

IO3 - --------->I-

IO3 - +3H2O ---------> I- + 6OH-

IO3- + 3H2O + 6e- ---------> I- +6OH- ----------(2)

By multiplying first equation with three and second equation with six,  we get our equation as-

3IO3- + 9H2O+6Cr(OH)3---------> 6(Cro4)2- +24H2O + 3I- + 18OH-

Then by simplifying, we get the balanced equation as-

IO3 - + 3H2O+2Cr(OH)3 ---------> 2CrO4 2- 8 H2O +I- 6OH-

-$Shahrin$ $Khan$