Cr2 o7²‐ assign oxidation number to the underlined elements in the below compounds
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Explanation:
a) Let x be the oxidation number of Mn in potassium permanganate KMnO
4
.
Since, the overall charge on the complex is 0, the sum of oxidation states of all elements in it should be equal to 0.
+1+x+4(−2)=0
x=+7
b) Let x be the oxidation number of Cr in chromyl chloride CrO
2
Cl
2
.
x+2(−2)+2(−1)=0
x=+6
c) Let x be the oxidation number of I in nitric acid NaIO
3
.
1+x+3(−2)=0
x=+5
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