Cr2O7²- + C2H4O→C2H4O2 + Cr3+
balance the following equation by ion electron method
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Cr2O72- + C2H2O- → C2H2O + Cr3+ ...(i) Here Cr2O72- → 2Cr3+ i.e., Cr2O72- → 2Cr3+ + 7H2O 6e- + 14H+ + Cr2O72- → 2Cr3+ + 7H2O [H2O + C2H4O- → C2H4O2 + 2H+ + 3e-] x 2 ...(ii) 10H+ + Cr2O72- + 2C2H4O- → 2C2H4O2 + 2Cr3+ + 5H2O...... answer
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