Crack the Code ?
Code
A Numeric Lock has a 3 Digit Key
HINT
Answers
Therefore, the co-de of the given numerical lock is 042.
Decoding the clues given:
On observing the rules given, from the fourth rule, we get that the lock contains no numbers from the list [7, 3, 8]. So, from the first rule 6, 2 remains.
From the second rule, we get that one number among 6, 1, 4 is correct but wrongly placed. But the number 6 is in the same position in rules 1 and 2. So, there is no chance of 6 being among the three numbers of the lock.
So, from the first rule, we get that the number at the last position is 2 as it says that the number is well placed.
_ _ 2
In the third rule, if we eliminate 6, the remaining numbers are 2, 0. They are correct but wrongly placed. As 2 is fixed with the last position, 0 goes for the first position as per the rule.
0 _ 2
Now, from rule 2, we get that one number is correct among 1, 4 but is wrongly placed. If 1 is correct, it would be well placed and that contradicts the rule which says that the number is wrongly placed. So, the correct number that should be in the second position is 4
0 4 2
Therefore, the co-de of the given numerical lock is 042.
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Using the given hints and explaining it one by one.
1) One number is correct and placed properly so it can be any number.
2) One number is correct but wrongly placed and from the above hint it is clear that 6 can't be that number.
3) Two numbers are correct and wrongly placed so from the above hints it can be 2, 0 and place for 2 is third box according to the first hint while 0 at first box.
4) we will not consider this as nothing is correct given here.
5) One number is correct that is so sure 0. And from the above hints we get the number as 042.
The code be 042.
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