Math, asked by bhaskarkalawat4307, 10 months ago

Crack the code numeric lock
189 147 964 523 286


amitnrw: Complete ur Question

Answers

Answered by amitnrw
2

Given :  Lock codes and condition

To find : Code of lock

Solution:

189 - one digit is right and in its place

147 - one digit is right but in wrong place

964 - two Digits are correct but in wrong place

523 - all Digits are wrong

286 - one digit is right but in wrong place

189  & 147 both have one digit right , but one in right place and one on wrong place

hence 1 can not be the Digit

523 - all Digits are wrong

286 - one digit is right but in wrong place  ( 2 is wrong digit)

=> 8 or 6 must be right digit

it can not be 8 as its in wrong place while

189 - one digit is right and in its place ( and position of 8 is same)

=> 8 is not right digit

hence  6 is right Digit  but in wrong place in 286

964 - two Digits are correct but in wrong place

=> 6 position must be 1st

189 - one digit is right and in its place ( 1 & 8 not possible)

Hence 9 is right digit at right place

=> 6 x 9

964 has 9 & 6 right digit hence 4 is wrong digit

147 - one digit is right but in wrong place

=> 7 is right digit in wrong place

=> 679  is code for lock

Learn more:

In a certain language HAPPY=3125 NANI=1024 then how key will ...

https://brainly.in/question/11580033

https://brainly.in/question/16427672

Attachments:
Similar questions