Question

crack the logic if 1 1 1 1 =R, 2 2 2 2 = T , 3 3 3 3 = E, 4 4 4 4 =N, 5 5 5 5 = O, then 6 6 6 6 =?

Answer 1

Given :  1 1 1 1= R   , 2 2 2 2= T  , 3 3 3 3= E  , 4 4 4 4=  N 5 5 5 5= O

To find : 6 6 6 6 = ?

Solution:

1 1 1 1= R

1 + 1 + 1 + 1 = 4  = FouR

Last letter of FouR is R

2 2 2 2= T

2 +2 + 2 +2 = 8 = EighT

Last letter of Eight is T

3 3 3 3= E

3 +3 + 3 +3 = 12 = 1 + 2 = 3 ThreE

E is Last letter

4 4 4 4= N

4 +4 + 4 +4 = 16 = 1 + 6 =  7  SeveN

N is Last letter

5 5 5 5 = O

5 +5 + 5 +5  = 20 = 2 + 0 = 2 TwO

O is last letter

6 6 6 6 = ?

6 + 6 + 6 + 6 =  24 = 2 + 4 = 6  SiX

X is last Letter

=> 6 6 6 6 = X

logic is : add all number  and the digits of resultant number

and then last letter of number in english  is the code

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*Can you crack the logic?* If 1 1 1 1= R 2 2 2 2= T 3 3 3 3= E 4 4 4 4 ...

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