Chemistry, asked by Saipreeth1447, 9 months ago

creasing order of hydrolysis of the following compounds is
Br Br Br
(CH3
)3 C Br
(i) (ii) (iii) (iv)
(a) (i)<(iii)<(ii)<(iv) (b)(i)<(iv)<(iii)<(ii)
(c) (iv)<(ii)<(iii)<(i) (d) (i)<(iii)<(iv

Answers

Answered by BearKnight
1

Answer:

NO

2

group and CHO group are electron withdrawing groups. They stabilize the carboxylate anion through negative resonance effect. Hence, compounds (II) and (IV) are more reactive towards hydrolysis than compound (I).

CH

3

group is electron releasing group. It destabilized the carboxylate anion through positive resonance effect. Hence, compound (III) is less reactive towards hydrolysis than compound (I).

Thus the order of the reactivity for hydrolysis reaction is II>IV>I>III

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