Math, asked by angelpatel2213, 9 months ago

Create a 7-digit number whose digits are in ascending order (from left to right) and that gives the same answer when rounded off to the nearest thousand and ten thousand?

Answers

Answered by nk596577052
0

Step-by-step explanation:

9999991,9999992,9999993,9999994,9999995,9999996,9999997,9999998,999999,100000000

Answered by TooFree
1

Given:

1) A 7-digit number

2) Digits are in ascending order

3) Gives the same answer when rounded off to nearest thousands or ten thousands

To Find:

The number

Solution:

Ascending order:

⇒  smallest to the biggest

To gives the same answer when rounded off to nearest thousands or ten thousands:

⇒ the digit in the thousands place must be a zero.

The digits in the number must be ascending:

⇒ Since the 4th digit needs to be a "zero", it is not possible to have all the digits ascending.

⇒ If we ignore the middle digit, the rest can be in ascending order

⇒ An example is 1230456

Answer: There is no possible answer, but if we ignore the middle digit with the rest ascending, the number can be 1230456.

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