Create a dictionary ‘ODD’ of odd numbers
between 1 and 10, where the key is the
decimal number and the value is the
corresponding number in words. Perform
the following operations on the dictionary:
i) display the keys
ii) display the values
iii) check if 7 is present or not
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ODD={1.0:'One',3.0:'Three',5.0:'Five',7.0:'Seven',9.0:'Nine'}
>>> ODD.keys()
dict_keys([1.0, 3.0, 5.0, 7.0, 9.0])
>>> ODD.values()
dict_values(['One', 'Three', 'Five', 'Seven', 'Nine'])
7.0 in ODD
True
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