Question

Create a function that computes the approximation of pi, based on the number of iterations specified, pi can be computed by 4*(l-l/3+l/5-l/7+l/9-…).

Answer 1

Answer:

int calPi(int n)

{

      double pi=1;

      for(int i=1;i<=n;i++)

      {

        if(i%2==1){pi=pi-1/(2i+1);}

        else{ pi=pi+1/(2i+1);}

      }

     return pi

}

Explanation:

Answer 2

The function that calculates the approximation of pi is as follows:

def approx(n):                  //function

x = 1                                 // declared variable x

a = 0                               // declared variable a

while x<=n:                     // while loop

a = a + ((4/float( 2* x- l ) n-l )* *( x + l ) )           // formula to calculate pi

i = i + l

return a