Question

Create a problem where the answer is two different kinds of polygons with their interior angles having combined sum of 4860 degrees.
(I don't really need you to create a problem, but just find these two polygons and explain how you got them PS: they have to be two different polygons)

Answer 1

The sum of interior angles of a polygon with n sides = (n-2) 180°

Let us say, we have two polygons with their sum of interior angles 4860°

Let us split 4860° into two distinct parts, of which, each is a multiple of 180°

By trail and error, the combination 900° and 3960° would be perfect. (P.S. You can just take any combination, each of which when divided be 180, add up to 29.)

According to formula,
900° = (n-2) 180°
5 = (n-2)
n = 7

And, for another polygon,
3960° = (N-2) 180°
22= (N-2)
N = 24

Therefore, a polygons with 7 and 24 sides will have the interior angles added up to 4860°.
Therefore, the question could be,

"Find of sum of interior angles of a heptagon and a 24-gon."

Cheers!