Question

Create a program in Python to find if a year is a leap year or not (a leap year is divisible by 4). if its correct i will give 100 points only today in 5 min

Answer 1

Answer:

1. year = int(input("Enter a year: "))
2. if (year % 4) == 0:
3. if (year % 100) == 0:
4. if (year % 400) == 0:
5. print("{0} is a leap year". format(year))
6. else:
7. print("{0} is not a leap year". format(year))
8. else:

Explanation: