Question

Create a program that prompts for a positive number greater than 2 (check this condition) and

then keeps taking the square root of this number until the square root is less than 2. Print the value

each time the square root is taken, along with the number of times the operation has been

completed. For example:

Enter an integer greater than 2: 20

1: 4.472

2: 2.115

3: 1.454​

Answer 1

$\large\mathsf\color{pink}{Solution\: using\: python\: 3}$

import math

def sqrt(n):

sqrt = n

counter = 0

while sqrt > 2:

sqrt = math.sqrt(sqrt)

counter += 1

print(f"{counter}: {sqrt}")

while True:

n = int(input("enter a num > 2: "))

if n <= 2:

print("enter a number > 2!")

continue

else:

sqrt(n)

break

$\large\mathsf\color{lightgreen}useful?\: \color{white}\longrightarrow\: \color{orange}brainliest!$

Answer 2

Answer:

import math

def sqrt(n):

sqrt = n

counter = 0

while sqrt > 2:

sqrt = math.sqrt(sqrt)

counter += 1

print(f"{counter}: {sqrt}")

while True:

n = int(input("enter a num > 2: "))

if n <= 2:

print("enter a number > 2!")

continue

else:

sqrt(n)

break