Question

cres Po, P1, P2, ... are placed at rest on the x-axis. The position coordinate of the particle P
s given that x = 0 and x< x < x, < x, etc. At time t=0, Po starts from rest and
moves in the positive x-direction with constant acceleration of 2m/sec? and collides with Piat
sec. Subsequently, each particle collides with the particle on its right. The duration of
cach of these collisions is zero. When particle Pi collides with particle Pi+1 at the instant t with
TOCHY V,, the velocities of Pi and Pi+1 abruptly become zero and 11+ at the same instant
is given that u; +1 = The particles move with constant accelerations in the positive -
direction in between collisions. The acceleration of P; between collisions is a,. It is given that
4+1 = 2a. The collision between particles Pi and Pi+ı takes place at the instant 1,. It is given
that 1+1 = 1; +2 sec.
9. The value of t, is
a) zero
10.
b) 2 sec
c) 4 sec
d) 6 sec
The value of u, is
a) 2m/s
b) 4m/s
c) 5m/s
11.
d) 10m/s
The value of x - xz is
a) 12m
b) 14m
c) 26m
d) 1987
​

Answer 1

Answer:

Explanation:

Yes

Answer 2

Answer:

X = at² - bt³

increasing speed implies change in speed per unit time . e.g a = dv/dt .

what's more, we additionally know, speed is change in relocation per unit time .e.g v = dx/dt consequently,

quickening = d²x/dt²

now, separate x = at² - bt³

as for t dx/dt = 2at - 3bt² t = a/3b