Cricket ball of mass 0.2 kg is moving with a velocity of 1.2 metre per second find the impulse on the ball and the average applied by the player is he is able to stop the ball in 0.1 second
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m = 0.2 kg
u = 1.2 m/s
v = 0 (as the player stops the ball)
t = 0.1 s
a = -12 m/s²
F = ma
= 0.2×(-12)
= -2.4 N
Impulse = F×t
= -2.4×0.1
= -0.24 N s
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