cricket ball of mass 120 g moving with a speed of 100m/s pierces through a sack of sand 10 cm thick and comes out with a velocity of 60m/s.Determine the average force exerted by sand on ball
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Answered by
4
Given:
m =120g= 0.12kg
initial speed (u)=100m/s
final speed = v= 60m/s
s= 10cm= 0.1m
by equations of motion,
V square - u square =2as
60* 60- 100*100= 2* a *0.1
a=6400m/s2
F= mxa
=
0.12* 6400
=768 N
therefore force exerted by sand. on ball is 768N
m =120g= 0.12kg
initial speed (u)=100m/s
final speed = v= 60m/s
s= 10cm= 0.1m
by equations of motion,
V square - u square =2as
60* 60- 100*100= 2* a *0.1
a=6400m/s2
F= mxa
=
0.12* 6400
=768 N
therefore force exerted by sand. on ball is 768N
prmkulk1978:
The Above Ans. Was Incorrect Plz Check This Solution
V^2 - U^2 = 2as
WKT a = F/m
We Get a = -3200 F= ma So F= 0.12 x (-3200) = - 3840 N The For Exerted by sand on Ball is +3840 N
Answered by
4
Mass= 0.12 kg
V1= 10
V2=60
distance= s= 0.1m
V2²= V1²+2as
a=17500 m/s²
Force=ma
F=2100N
V1= 10
V2=60
distance= s= 0.1m
V2²= V1²+2as
a=17500 m/s²
Force=ma
F=2100N
Given Initial Velocity is Not 10m/s It is 100 m/s.
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