Question

Cricket ball of mass .16 kg. moving with a speed of 20 metre per second is brought to rest by a player in .1 second what is the average force applied by the player​

Answer 1

Answer:

Correct option is

C

100N

I guess the question is the rate of change in momentum

Mass=0.1kg

Initial Momentum=m×speed (u)=0.1×30=3

Final Momentum= m×rest (v)=0.1×0=0

Change in Momentum= Final-Initial =0−3=−3

Rate of change in momentum=(change in momentum)÷time taken

=(−3)÷0.03

=−100

Hence,

option (C) is correct answer.

Explanation:

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Answer 2

Answer:

The average force applied by the player is 32 newton.

Explanation:

from the equation,

F = ma

or, F = m × (v-u)/t

[where F = force applied by the player ,

m = mass of the ball = .16 kg ,

a = acceleration of the ball ,

u = primary velocity of the ball = 20 m/s ,

v = final velocity of the ball = 0 and

t = time taken by the ball to come to rest = .1 s]

so, F = .16 × (20-0)/.1 = .16 × 200 = 32 newton.