Question

cricket bowl thrown upward with velocity,196m/second? up to what maximum height it attained.

Answer 1

HOLA! !!

HERE YOUR ANSWER IS

GIVEN

initial velocity (u ) = 196m/S

final velocity (v) = 0 ( since it reaches the maximum height, at the maximum height the object experiences no velocity)

maximum height = ?

SOLUTION

we know v = u +at

time = v-u/a

=( 196 -0) /(9.8)

(since acceleration at certain point would be 9.8ms^-2)

t = 20s

v^2- u^2 = 2as

0^- (196)^2 = 2 (9.8)(s)

-38416 /19.6 = s

s = 1960 m





HOPE IT HELPS YOU! !!!

Answer 2

Answer:

initial velocity (u ) = 196m/S

final velocity (v) = 0 ( since it reaches the maximum height, at the maximum height the object experiences no velocity)

maximum height = ?

SOLUTION

we know v = u +at

time = v-u/a

=( 196 -0) /(9.8)

(since acceleration at certain point would be 9.8ms^-2)

t = 20s

v^2- u^2 = 2as

0^- (196)^2 = 2 (9.8)(s)

-38416 /19.6 = s

s = 1960 m