cricketer of height 2.5 M throws a ball at an angle of 30 degree with the horizontal such that it is received by another cricketer of same height standing at distance of 50 m from the first one. find the maximum height attained by the ball.
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9.8m is the maximum height.
shaun100:
please send the steps
Range = 4 x maximum height. The answer is 12.5m.
answer is given 9.8m
Range =50m, u = 100/[3^1/2], Max height total= [(u^2 x sin^2 (x))/2g] + 2.5 = 9.8 nearly.
yes it is right now
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