critically evaluate larentz transformatation equation
Answers
Answer:
Lorentz transformation is the relationship between two different coordinate frames that move at a constant velocity and are relative to each other. The name of the transformation comes from a Dutch physicist Hendrik Lorentz.
There are two frames of reference, which are:
Inertial Frames – Motion with a constant velocity
Non-Inertial Frames – Rotational motion with constant angular velocity, acceleration in curved paths
Lorentz transformation is only related to change in the inertial frames, usually in the context of special relativity. This transformation is a type of linear transformation in which mapping occurs between 2 modules that include vector spaces. In linear transformation, the operations of scalar multiplication and additions are preserved. This transformation has a number of instinctive features, such as the observer that is moving at different velocity may measure elapsed times, different distances, and ordering of events but the condition that needs to be followed is that the speed of light should be the same in all the inertial frames.
Lorentz transformation can also include rotation of space, a rotation that is free of this transformation is called Lorentz Boost. The space-time interval which occurs between any two events is preserved by this transformation.
Lorentz Transformation Formula
Following are the mathematical form of Lorentz transformation:
t
′
=
γ
(
t
−
v
x
c
2
)
x
′
=
γ
(
x
−
v
t
)
y
′
=
y
z
′
=
z
Where,
(t,x,y,z) ans (t’,x’,y’,z’) are the coordinates of an event in two frames
v is the velocity confined to x-direction
c is the speed of light
Lorentz Transformation Equations
In the reference frame ‘F’ which is stationary, the coordinates defined are x, y, z, t. In another reference frame F’ which moves at a velocity v which is relative to F and the observer defines coordinates in this moving reference frames as x’ , y’ , z’ , t’. In both the reference frames the coordinate axis are parallel and they remain mutually perpendicular. The relative motion is along the xx’ axes. At t = t’ = 0, the origins in both reference frames are same (x,y,z) = (x’,y’,z’) = (0,0,0)
If the events x, y, z, t are recorded in reference frames F then in F’ these coordinates have the following value:
x
‘
=
x
−
v
t
√
1
−
v
2
c
2
t
‘
=
t
−
v
x
c
2
√
1
−
v
2
c
2
y
′
=
y
z
′
=
z
γ
=
1
√
1
−
v
2
c
2
Here lowercase gamma is the Lorentz factor