cross multiplication
first one
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2 i
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tushar51:
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Given pair of linear equations,
x-y=a+b........................................1
ax+by=a²-b²................................2
eq1 and eq2 can also be written as,
x-y-(a+b)=0..................................3
ax+by-(a²-b²)=0...........................4
Here,
a1=1 , a2=a , b1=-1 , b2=b , c1=-(a+b)
c2=-(a²-b²)
from picture we get,
x/a(a+b) = -y/b(a+b) = 1/(a+b)
x/a(a+b)=1/(a+b) and -y/b(a+b)=1/(a+b)
x/a=1 and -y/b=1
x=a and y=-b
Hence solution of given pair of linear equation=(a,-b).
x-y=a+b........................................1
ax+by=a²-b²................................2
eq1 and eq2 can also be written as,
x-y-(a+b)=0..................................3
ax+by-(a²-b²)=0...........................4
Here,
a1=1 , a2=a , b1=-1 , b2=b , c1=-(a+b)
c2=-(a²-b²)
from picture we get,
x/a(a+b) = -y/b(a+b) = 1/(a+b)
x/a(a+b)=1/(a+b) and -y/b(a+b)=1/(a+b)
x/a=1 and -y/b=1
x=a and y=-b
Hence solution of given pair of linear equation=(a,-b).
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