Question

Cross multiplication method of
3x-3y=3
2x-5y=4
​

Answer 1

Answer:

The given equations may be written as: 2x + 5y – 1 = 0 …….(i) 2x + 3y – 3 = 0 …….(ii) Here a1 = 2, b1 = 5, c1 = -1, a2 = 2, b2 = 3 and c2 = -3 By cross multiplication, we have: Read more on Sarthaks.com - https://www.sarthaks.com/130944/solve-the-system-of-equations-by-using-the-method-of-cross-multiplication-2x-5y-1-0-2x-3y-3-0

Answer 2

Answer:

The value of x is = 1/3

And the value of y is = -2/3

Step-by-step explanation:

3x - 3y = 3

2x - 5y = 4

Now, We have to solve this equation by cross multiplication method,

So, Appling cross multiplication method on

3x - 3y - 3 = 0 and 2x - 5y - 4 =0, we get,

X/(( -3×-4) -(-3×-5)) =Y/((-3×2) -(3×-4)) =1/((3×-5) -(-3×2))

This implies, X/(12-15) =Y/(-6+12) =1/(-15+6)

i,e. X/-3=Y/6=1/-9

This implies, X/-3 = 1/-9 and Y/6 = 1/-9

So, X = -3/-9 and Y = 6/-9

So, X = 1/3 and Y = -2/3