Math, asked by ShuchiRecites, 1 year ago

Cross Multiply these two equations:

5x - 2y - 2 = 0
2x + 3y - 16 = 0

Also tell me that how you did it?

Have a Good Day ahead!☺

Answers

Answered by siddhartharao77
9
Given Equation is 5x - 2y - 2 = 0   ------- (1)

a1 = 5, b1 = -2, c1 = -2.

Given Equation is 2x + 3y - 16 = 0  ------- (2)

a2 = 2, b2 = 3, c2 = -16.


Now,

x =  \frac{b1c2 - b2c1}{a1b2 - a2b1}

          =  \frac{(-2)(-16) - (3)(-2)}{(5)(3) - (2)(-2) }

          =  \frac{32 + 6}{15 + 4}

           = \frac{38}{19}

          = 2


Now,

y =  \frac{c1a2 - c2a1}{a1b2 - a2b1}

           =  \frac{(-2)(2) - (-16)(5)}{(5)(3) - (2)(-2)}

            = \frac{-4 + 80}{15 + 4}

            = \frac{76}{19}

           = 4



Therefore x = 2, y = 4.


Hope this helps!

siddhartharao77: Any doubts. Ask me. Gud luck!
ShuchiRecites: How did u formed the first equation?
ShuchiRecites: x = ( b1c2-b2c1 ) / ( a1b2 - a2b1 )
ShuchiRecites: Ok, I got it !
ShuchiRecites: Heartly Thanks, Good Night
siddhartharao77: Ok
Answered by ravanji786
1

Answer:

SEE THE ATTACHMENT FOR DETAILED SOLUTION TO THE QUESTION DEAR

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