Question

cross product of A=2i-3j+k and B= -i+3j+k

Answer 1

Answer:

Let vector(A)= 2i -3j -k

and vector(B)= -6i +9j +3k

therefore AXB= A.BSinθ

LHS=>

AXB=0 {By solving using cross product method for vectors}

RHS=>

A.B=-42 {By solving using dot product method for vectors}

Now coming to the formula,

when θ=0 or 180, the two vectors are parallel.

So,

(AXB)/A.B

=0/-42

=0

Sinθ=0

therefore, θ=0.

hence vectors 2i-3j-k and -6i+9j+3k are parallel

Hope this was helpful!