Cross product of (i + j+k) and 2i+
3j+k) + is
Answers
Answered by
0
Answer:
0=I+2j
Explanation:
(I+j+k)/1 = (2i+3j+k)/1
I+j+k=2i+3j+k
j+k=2i-i+3j+k
j+k=I+3j+k
k-k=I+3j-j
0=I+2j
hope this helps you
Similar questions