cross section of ladies finger vegetable in vertical and horizontal cut
Answers
Answer:
Step-by-step explanation:
In ∆ AOB, OD is the bisector of angle AOB
OA/OB =AD/DB---------------eq(1)
Theorem used here
[The internal bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle]
In ∆BOC .OE is the bisector of angle BOC
OB/OC = BE/EC---------eq(2)
In ∆COA, OF is the bisector of angle COA
OC/OA =CF/FA-----------eq(3)
Multiplying eq 1, 2, 3
(OA/OB) * (OB/OC) * (OC/OA) = (AD/DB) * (BE/EC) * (CF/FA)
1= (AD/DB) * (BE/EC) * (CF/FA)
DB*EC*FA = AD*BE*CF
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AD*BE*CF = DB*EC*FA
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Hope this will help you.....
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Answer:
Step-by-step explanation:
use mendels formula, it will give a dominant one